Cara Mengerjakan Soal MEKANIKA BAHAN

0<x<1,6

Mx         = VA . x

X             = 1,6

Mx         = 2 x 1,6

                = 3,2

0<x<2,4

Mx         = VA . x – p(0,8)

X             = 0

Mx         = 1,6

X             = 2,4

Mx         = 2 x2,4 – 2(0,8)

                = 4,8 – 1,6

                = 3,2

0<x<3,2

X             = 3,2

Mx         = VA.x – p(x-1,6) – q(0,8)

                = 6,4 -3,2 – 5,2

                = -2

X             = 0

Mx         = 3,2 – 5,2

                =2

0<x<4,8

Mx         = VA.x – p(x-1,6) – q(x-2,4) – p(1,6)

X             = 0

Mx         = 3,2 + 15,6 – 3,2

                = 15,6

X             = 4,8

Mx         = 9,6 – 6,4 - 15,6 – 3,2   

                = 9,6 -25,2

                = - 15,6

       Jawaban Soal no 3

Py           = P x Cos Ɵ

                = 2,56 x Cos 22,5

                = 2,365

Px           = P x Sin Ɵ

                = 2,56 x Sin 22,5

                = 0, 979

My         = 2,365 x 2

                = 4,73

Mx         = 0,979 x 2

                = 1,958

Ix            = 1/12 . b . h³ – 2(1/12 . b.h³)

                =1/2 . 20 . 28,5³ – 2(1/12. 9 25³)

                = 38581,875 – 23437,5

                = 15108,375

Ix            = 1/12 . 28,5 .20³ – 2(1/12 . 25 . 9³)

                = 19000 – 3037,5

                = 15962,5

Akibat P₁             

√A          = M . yA/Ix

                = 4,73 . 10⁴ . 20/ 15108,375

                = 62,6122

Akibat P2

                = 1,958 . 10⁴ . 9/ 15962,5

                = 11,03